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On squared distance matrix of complete multipartite graphs

Joyentanuj Das () and Sumit Mohanty ()
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Joyentanuj Das: National Sun Yat-sen University
Sumit Mohanty: IIM Ranchi

Indian Journal of Pure and Applied Mathematics, 2024, vol. 55, issue 2, 517-537

Abstract: Abstract Let $$G = K_{n_1,n_2,\cdots ,n_t}$$ G = K n 1 , n 2 , ⋯ , n t be a complete t-partite graph on $$n=\sum _{i=1}^t n_i$$ n = ∑ i = 1 t n i vertices. The distance between vertices i and j in G, denoted by $$d_{ij}$$ d ij is defined to be the length of the shortest path between i and j. The squared distance matrix $$\Delta (G)$$ Δ ( G ) of G is the $$n\times n$$ n × n matrix with $$(i,j)^{th}$$ ( i , j ) th entry equal to 0 if $$i = j$$ i = j and equal to $$d_{ij}^2$$ d ij 2 if $$i \ne j$$ i ≠ j . We define the squared distance energy $$E_{\Delta }(G)$$ E Δ ( G ) of G to be the sum of the absolute values of its eigenvalues. We determine the inertia of $$\Delta (G)$$ Δ ( G ) and compute the squared distance energy $$E_{\Delta }(G)$$ E Δ ( G ) . More precisely, we prove that if $$n_i \ge 2$$ n i ≥ 2 for $$1\le i \le t$$ 1 ≤ i ≤ t , then $$ E_{\Delta }(G)=8(n-t)$$ E Δ ( G ) = 8 ( n - t ) and if $$ h= |\{i: n_i=1\}|\ge 1$$ h = | { i : n i = 1 } | ≥ 1 , then $$\begin{aligned} 8(n-t)+2(h-1) \le E_{\Delta }(G)

Keywords: Complete t-partite graphs; Squared distance matrix; Inertia; Energy; Spectral radius; 05C12; 05C50 (search for similar items in EconPapers)
Date: 2024
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DOI: 10.1007/s13226-023-00386-2

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